make x column

This commit is contained in:
emil28092005
2024-09-20 22:15:57 +03:00
parent 8e6024a01e
commit b073126348
4 changed files with 235 additions and 138 deletions
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# Prerequisites
*.d
CMakeLists.txt
.idea
# Compiled Object files
*.slo
*.lo
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#include <iostream>
#include "tools/matrix.h"
int main() {
std::cout << "Hello World!\n";
int n, m;
ColumnVector C(n);
Matrix A(n, m);
ColumnVector b(n);
double eps;
double eps_default;
std::cin >> C;
std::cin >> A;
std::cin >> b;
std::cin >> eps;
return 0;
}
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// implementation of simplex task
#include <algorithm>
#include <iostream>
#include "tools/matrix.h"
enum solver_state {
unbounded,
bounded
};
struct Result {
solver_state state;
ColumnVector *solution;
double objective_fucntion_value;
};
Result Simplex(ColumnVector C, Matrix A, ColumnVector b, double eps = 0.01, bool maximize) {
Result result;
std::vector<int> basicVars(A.getColumns() - A.getRows());
basicVars[0] = -1;
for (int i = 1; i < basicVars.size(); i++) {
basicVars[i] = static_cast<int>(basicVars.size()) + i;
}
int kc = 0;
double temp = A[0][0];
for (int j = 0; j< A.getColumns(); j++) {
if (A[0][j] < temp) {
temp = A[0][j];
kc = j;
}
}
if (A[0][kc] >= 0) {
result.state = unbounded;
result.solution = new ColumnVector(C.getRows());
for (int i = 0; i < C.getRows(); i++) {
result.solution->operator[](i) = 0;
}
for (int i = 1; i < basicVars.size(); i++) {
if (basicVars[i] <= C.getRows()) {
(*result.solution)[basicVars[i]] = b.getRows() - 1;
}
}
result.objective_fucntion_value = b[0];
}
}
/*
Function_name(C, A, b, eps = eps_default)
Input:
- C: A vector of coefficients of the objective function
- A: A matrix of coefficients of the constraint functions
- b: A vector of right-hand side values
- eps: Approximation accuracy (optional, default = eps_default)
Steps:
1. Print the optimization problem:
- max (or min) z = C[0] * x1 + C[1] * x2 + ... + C[n] * xn
- subject to the constraints:
- A[0] * x <= b[0]
- A[1] * x <= b[1]
- ...
- A[m] * x <= b[m]
2. Initialize:
- Form the initial tableau by introducing slack variables to convert inequalities into equalities.
3. Iteratively apply the Simplex method:
- Step 1: Identify the entering variable (most negative coefficient in the objective row).
- Step 2: Identify the leaving variable (smallest positive ratio of RHS to pivot column).
- Step 3: Perform pivot operations to update the tableau.
4. Check for optimality or unboundedness:
- If all coefficients in the objective function row are non-negative, the solution is optimal.
- If no leaving variable exists, the problem is unbounded.
5. Return:
- solver_state: {solved, unbounded}
- x*: Optimal vector of decision variables (if solved)
- z: Maximum (or minimum) value of the objective function (if solved)
End Function
*/