Files
SimplexTASK/simplex.cpp
T
emil 5c2f80f85a Make appropriate outputting.
Fix Makefile and add optional rebuild shorcut function.
Fix outputs in simplex.cpp
2024-10-08 03:17:13 +03:00

166 lines
4.3 KiB
C++

#include <algorithm>
#include <iostream>
#include "tools/matrix.h"
#include "tools/math.h"
#include "tools/elimination.h"
enum solver_state {
unbounded,
bounded,
unsolvable
};
struct Result {
solver_state state;
Vector solution;
double objective_function_value;
bool maximize;
};
void _printInitialInputs(Vector& C, Matrix& A, Vector& b) {
}
void _stopIterating(Matrix& generalMatrix, Vector& C, std::vector<int>& basicVars, solver_state state, Result& result) {
DestroyMatrix destroyedGeneralMatrix = disassembleGeneralMatrix(generalMatrix);
Matrix _A = destroyedGeneralMatrix.A;
Vector _C = destroyedGeneralMatrix.C;
Vector _b = destroyedGeneralMatrix.b;
result.state = state;
if (state == bounded) {
result.solution = Vector(C.size());
for (int i = 0; i < C.size(); i++) {
result.solution[i] = 0;
}
for (size_t i = 1; i < basicVars.size(); i++) {
if (basicVars[i] < C.size()) {
result.solution[basicVars[i]] = _b[i];
}
}
result.objective_function_value = _b[0];
} else {
result.solution = Vector({0});
result.objective_function_value = 0;
}
}
/*
Implementation of the Simplex method.
*/
Result simplex(Vector& C, Matrix& A, Vector& b, double eps = 0.01, bool maximize=true) {
if (maximize == true) {
for (int i = 0; i < C.size(); i++) {
C[i] = -C[i];
}
}
Result result{};
result.maximize = maximize;
Matrix generalMatrix = createGeneralMatrix(A, C, b);
std::cout << generalMatrix;
std::vector<int> basicVars(generalMatrix.getRows());
basicVars[0] = -1;
for (int i = 0; i < b.size(); ++i) {
if (b[i] < 0) {
_stopIterating(generalMatrix, C, basicVars, unsolvable, result);
return result;
}
}
for (size_t i = 1; i < basicVars.size(); i++) {
basicVars[i] = static_cast<int>(basicVars.size()) + i;
}
int iterationCount = 0;
while (true) {
//3
iterationCount++;
int pivot_column_index = 0;
pivot_column_index = min_index(generalMatrix[0]);
if (generalMatrix[0][pivot_column_index] >= 0) {
_stopIterating(generalMatrix, C, basicVars, bounded, result);
if (!maximize) {
result.objective_function_value = -result.objective_function_value;
}
return result;
}
//4
Vector ratio_vector(generalMatrix.getRows());
for (int i = 1; i < generalMatrix.getRows(); i++) {
if (generalMatrix[i][pivot_column_index] != 0) {
ratio_vector[i] = generalMatrix[i][generalMatrix.getColumns() - 1] / generalMatrix[i][pivot_column_index];
if (std::abs(ratio_vector[i]) < eps) {
ratio_vector[i] = 0;
}
} else {
ratio_vector[i] = 0;
}
}
ratio_vector[0] = 0;
int pivot_row_index = min_index_positive(ratio_vector);
// No leaving variable exists
if (pivot_row_index == -1) {
_stopIterating(generalMatrix, C, basicVars, unbounded, result);
return result;
}
basicVars[pivot_row_index] = pivot_column_index;
//5
elimination(generalMatrix, pivot_row_index, pivot_column_index);
std::cout << "Iteration "<< iterationCount << " " << std::endl;;
std::cout << generalMatrix;
}
//result.state = solved;
//std::cout << result.state;
return result;
}
/*
Function_name(C, A, b, eps = eps_default)
Input:
- C: A vector of coefficients of the objective function
- A: A matrix of coefficients of the constraint functions
- b: A vector of right-hand side values
- eps: Approximation accuracy (optional, default = eps_default)
Steps:
1. Print the optimization problem:
- max (or min) z = C[0] * x1 + C[1] * x2 + ... + C[n] * xn
- subject to the constraints:
- A[0] * x <= b[0]
- A[1] * x <= b[1]
- ...
- A[m] * x <= b[m]
2. Initialize:
- Form the initial tableau by introducing slack variables to convert inequalities into equalities.
3. Iteratively apply the Simplex method:
- Step 1: Identify the entering variable (most negative coefficient in the objective row).
- Step 2: Identify the leaving variable (smallest positive ratio of RHS to pivot column).
- Step 3: Perform pivot operations to update the tableau.
4. Check for optimality or unboundedness:
- If all coefficients in the objective function row are non-negative, the solution is optimal.
- If no leaving variable exists, the problem is unbounded.
5. Return:
- solver_state: {solved, unbounded}
- x*: Optimal vector of decision variables (if solved)
- z: Maximum (or minimum) value of the objective function (if solved)
End Function
*/